SSC JE Electrical Engineering 2015 Paper

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Question : 184 of 199

Marks: +1, -0

Mutual inductance between two coils is 4 H. If current in one coil changes at the rate of 2A/sec, then emf induced in the other coil is?

8 V
2 V
0.5 V
5.0 V

Solution:

Emf =

L{di}/{dt}=4 × 2 = 8

volt

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