SSC JE Electrical Engineering 2017 Set 1 Paper

Question : 111 of 200

Marks: +1, -0

In a parallel circuit operating with a source of 30 V AC, designed to carry a total current of 6A, what happens to the protection device (fuse) when the resistance suddenly change to 2Ω

It closes
There is no change
It shorts to ground
It opens

Validate

Solution:

Designed to carry total current = 6A
if 2Ω Resistance

When resistance changes to 2Ω then
then

30/2= 15A

15A current will melt the fuse because total current flow is higher then normal current of fuse and circuit is open

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