SSC JE Electrical Engineering 2017 Set 1 Paper

Question : 134 of 200

Marks: +1, -0

Find current

l_1, l_2

and

l_3

respectively in the given figure.

Solution:

V_1/4+ V_1/5+ V_ 1/ 1 =8

V_1 = 5.51 V

I _1 = 5.51/4= 1.38A

I_ 2 = 5.51 /5=1.102A

I_ 3 = 5.51/1= 5.51A

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