SSC JE Electrical Engineering 2017 Set 2 Paper

Question : 163 of 200

Marks: +1, -0

A 4-pole, lap wound, D.C generator has the following details :
Flux = 0.07 web/pole, speed = 900r.p.m, Armature conductore = 440.
The generated e.m.f.is ___:

400 V
502 V
462 V
900 V

Validate

Solution:

Pole ‘P’ = 4
Flux per pole ‘Q’ = .07 wb//pole
Speed ‘N’ = 900 rpm
Armature conductor (z) = 440
Lap wound generator the number of parallel conductor ‘A’ = No. of pole ‘P’ = 4
Emf =

{ϕZPN}/{60A}={.07× 440× 900 ×4}/{60×4}

= 462 volt

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