SSC JE Electrical Engineering 2017 Set 3 Paper

Capacitance across two parallel plate capacitor
$\mathit{C}=∊\frac{\mathit{A}}{\mathit{d}}$
where A is Cross section area of plate
where d is Distance between two plate
If plate area of parallel plate capacitor increase the capacitance increase
$\left[\mathit{C}\propto \mathit{A}\right]$
$\mathit{C}=\frac{\mathit{q}}{\mathit{V}}$
at constant voltage by increasing plate area, increase charges.
$\mathit{F}=\mathit{q}\mathit{E}$
$\mathit{I}\propto \mathit{q}$
If charge increase, the force between the plate also increase.