SSC JE Mechanical Engineering 2013 Paper

Question : 103 of 200

Marks: +1, -0

In a Hartnell governor, 800 N force is exerted on the sleeve at minimum radius and 1200 N force is exerted at maximum radius. If sleeve lift is 20 mm, the value of spring-stiffness (s) is

10 N/mm
20 N/mm
15 N/mm
18 N/mm

Validate

Solution:

Spring force F = R(x)
For Hartnell governor

[F_{r_1}- F_{r_2}= R(x)]

1200 -800 = R(20)

Spring stiffness

[R= 20 \N\/\m]

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