SSC JE Mechanical Engineering 2015 Paper

Question : 117 of 200

Marks: +1, -0

A heat engine receives 1000 kJ of heat and produces 600 kJ of work. The amount of heat rejected in kJ and the efficiency percentage of the engine, respectively will be:

400, 40%
400, 60%
600, 40%
600, 60%

Validate

Solution:

By 1

^{\st}

Law
ΣQ = ΣW

Q_1 -Q_2 = 600

Q_2 = 400

η= {o\/p} /{i\/p}=600/1000=60%

So, the amount of heat reflected is 400 kJ and the efficiency is 60%.

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