SSC JE Mechanical Engineering 2015 Paper

Question : 181 of 200

Marks: +1, -0

Two springs of stiffness

k_1

and

k_2

respectively are connected in series, what will be the stiffness of the composite spring?

Solution:

1/k_\eq=1/k_1+1/k_2= {k_1 ×k_2}/{ k_1+ k_2 }

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