SSC JE Mechanical Engineering 2017 Set 1 Paper

Question : 104 of 200

Marks: +1, -0

The ratio of the thickness of thermal boundary layer to the thickness of hydrodynamic boundary layer is equal to (prandtl number) n, where n is____.

Solution:

(\Pr)^n=δ/{δt}

(\Pr)^3=δ/{δt}

(\Pr)^ {-1/3}=δ/{δt}

n=-1/3

δ=

Hydrodynamic boundary layer

δt =

Thermal Boundary layer

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