SSC JE Mechanical Engineering 2018 Set 3 Paper

Question : 118 of 200

Marks: +1, -0

A rod with a length of 100 cm and diametre of 4 cm undergoes an axial pull of 50 kN. What is the stress (in N/mm

^{2 }

Solution:

d = 4 cm = 40 cm, P = 50 KN = 50 × 10

^{3}

N
stress

(σ)=P/ A

={50 ×10^3}/{π/4×(40)^2} =39.8\N \/ \mm^2 ≅ 40

N / mm

^2

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