SSC JE Mechanical Engineering 2018 Set 3 Paper

Question : 130 of 200

Marks: +1, -0

What will be the value of Poisson’s ratio, if the elasticity and rigidity of the material is 200 GPa and 66.67 GPa?

Solution:

We know E = 2 C (1 + µ)
200 = 2 × 66.67 (1 + µ)
⇒

200/133.34-1=µ=0.999≅0.50

µ=0.50

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