SSC JE Mechanical Engineering 2018 Set 3 Paper

Question : 132 of 200

Marks: +1, -0

What is the amount of maximum work that can be extracted from a Carnot engine working between temperature 1000 K and 100 K?

Solution:

Efficiency of carnot engine

=1-T_2/T_1={\Max \work}/{\heat \supplied}

=1-100/1000

= .90 or 90%

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