SSC JE Mechanical Engineering 2018 Set 5 Paper

Question : 121 of 200

Marks: +1, -0

The equivalent bending moment for a shaft which is subjected to the combined twisting moment (T) and bending moment (M) is given by equation ________.

$1/2[√{M^2+T^2}]$
$[√{M^2+T^2}]$
$1/2[M+√{M^2+T^2}]$
$[M+√{M^2+T^2}]$

Validate

Solution:

1/2[M+√{M^2+T^2}]

Equivalent Bending Moment : Equivalent bending moment which acting alone, will produce the same maximum principal stress or bending stress

Combined torque & bending

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