SSC JE Mechanical Engineering 2018 Set 5 Paper

Question : 178 of 200

Marks: +1, -0

The frictional resistance of a pipe varies approximately as
A. velocity of flow (v)
B.

v^2

√v

v^{3\/2}

Solution:

According to Darcy-Weisbach's formula, (frictionin pipe)

h_f={4fL}/D×v^2/{2g}

h_\f

is proportional to

v^2

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