If x is a positive quantity, then what is the value of 3x, if 0. \stackrel{¯}{423}−0.2 of 52.5 \div 0.84 = x^{2}−(0. \stackrel{¯}{021} + 12.5)?

SSC MTS 7 Oct 2021 Shift 2 Paper

Question : 71 of 100

Marks: +1, -0

If x is a positive quantity, then what is the value of 3x, if

0. \;{423}↖{¯}−0.2

52.5 ÷ 0.84 = x^{2}−(0. \;{021}↖{¯} + 12.5)?

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