SSE JE Electrical Engineering 10 Dec 2020 Papers

Question : 109 of 200

Marks: +1, -0

Select the correct answer with respect to the given network:

$- I _{1} R _{1}- I _{2} R _{2}- I _{3} R _{3}- I _{4} R _{4}+ E _{2}+ E _{1}=0$
$- I _{1} R _{1}- I _{2} R _{2}- I _{3} R _{3}- I _{4} R _{4}- E _{2}- E _{1}=0$
$- I _{1} R _{1}- I _{2} R _{2}+ I _{3} R _{3}- I _{4} R _{4}- E _{2}+ E _{1}=0$
$- I _{1} R _{1}- I _{2} R _{2}+ I _{3} R _{3}- I _{4} R _{4}= E _{2}+ E _{1}$

Solution:

Given circuit,

Total Voltage drop

= I _{1} R _{1}+ I _{2} R _{2}+(- I _{3} R _{3})+ I _{4} R _{4}

= I _{1} R _{1}+ I _{2} R _{2}- I _{3} R _{3}+ I _{4} R _{4}

Total Voltage rise

= E _{1}- E _{2}

According to KVL,
Total Voltage drop = Total Voltage rise

E _{1}- E _{2}= I _{1} R _{1}+ I _{2} R _{2}- I _{3} R _{3}+ I _{4} R _{4}

∴- I _{1} R _{ 1 }- I _{ 2 } R _{ 2 }+ I _{ 3 } R _{ 3 }- I _{ 4 } R _{ 4 }- E _{ 2 }+ E _{ 1 }= 0

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