SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

primary winding turns ${\mathrm{N}}_1=400$
secondary winding turns ${\mathrm{N}}_2=1000$
primary winding voltage ${\mathrm{V}}_1=500$
secondary winding voltage ${\mathrm{V}}_2=?$
Turns ratio or Voltage ratio: It is defined as the ratio of primary winding turns to secondary winding turns. It is denoted by 'a'.
$\mathit{a}=\frac{{\mathrm{N}}_1}{{\mathrm{N}}_2}=\frac{{\mathrm{V}}_1}{{\mathrm{V}}_2}$
$\therefore \frac{{\mathrm{V}}_1}{{\mathrm{V}}_2}=\frac{{\mathrm{N}}_1}{{\mathrm{N}}_2}$
$\Rightarrow \frac{500}{{\mathrm{V}}_2}=\frac{400}{1000}$
$\Rightarrow {\mathrm{V}}_2=1250\mathrm{V}$