SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

Question : 146 of 200

Marks: +1, -0

Suppose a plant that has installed capacity of 20 MW produces annual output of 7.35 × 106 kWh and remains in operation for 2190 hours in a year. Find the plant use factor.

14.5%
16.7%
18.5%
25.5%

Validate

Solution:

Station output

=7.35 × 10^{6} \kWh

=7.35 ×10^{3} \MWh

Plant capacity = 20 MW
Hours of use = 2190
Plant use factor

={7.35 ×10^{3}}/{20 ×2190} × 100=16.78 \%

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