SSE JE Electrical Engineering 29 Oct 2020 Shift 2 Papers

Question : 187 of 200

Marks: +1, -0

A device stores 500 J of energy and releases this energy in the form of an electric current of 40 A which has a duration of 15 msec. Determine the average voltage across the terminals of the device

860 V
790 V
833 V
800 V

Validate

Solution:

We know that
Energy W = Voltage × Current × Time
Voltage

= 500/ (40 × 15 × 10^{-3})

= 833 V

Go to Question:

Prev Question

Next Question