{\CH}_3 {\CH}_2 {\OH}{─\xrightarrow[443 {\K]{}}^{{\text{ Conc. } {\H}_2 {\SO}_4} } {\X}{──────▶}_{\text{ (2) } \ZnH_2\O}^{\text{ (1) } \O_3 }\Y_{\text{ (2 Moles) }}\stackrel{(\i) \Conc.\NaOH}{──\xrightarrow[(\ii) \H^{+]{}}Z Z is a mixture of alcohol and acid. Reaction of conversion of Y to Z is [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : Cannizzaro reaction

Carboxylic Acids and Its Derivatives

Section: Chemistry

Question : 5 of 9

Marks: +1, -0

CH3CH2‌OH‌

‌ Conc. ‌H2SO4

────────▶

443K

‌X‌

(1) ‌O3

──────▶

(2) ‌ZnH2O

‌

‌ (2 Moles) ‌

‌

(i)‌Conc.NaOH

─────────▶

(ii)‌H+

‌Z

Z is a mixture of alcohol and acid. Reaction of conversion of Y to Z is

[TG EAPCET 10 May 2024 Shift 1]

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