Time and Work Practice Test 3 with solutions

In 2 days work done by A and B = $\frac{1}{16}+\frac{1}{12}$ = $\frac{7}{48}$
In 6 pair of days work done by A and B = 6 × $\frac{7}{48}$ = $\frac{7}{8}$
Remaining part of work = 1 – $\frac{7}{8}$ = $\frac{1}{8}$
On 13th day work done by A = $\frac{1}{16}$
Remaining part of work = $\frac{1}{8}-\frac{1}{16}$ = $\frac{1}{16}$
Time taken by B in 14th day = $\frac{\frac{1}{16}}{\frac{1}{12}}$ = $\frac{12}{16}$ = $\frac{3}{4}$ day
Hence, total time taken = $13\frac{3}{4}$ days.