TS EAMCET 03 May 2019 Shift 2 Solved Paper

The following figure shows the final circuit of the series capacitor system
In a series capacitor system, the charge stored in the system is equal to,
Q=CeqV
Calculate the value of Ceq
Ceq‌‌=‌

4×8

4+8

‌‌=‌

8

3

µF
Therefore,
Q‌‌=‌

8

3

×6
‌‌=16µC
Calculate the value of V1
V1‌‌=‌

Q

C1

‌‌=‌

16

4

‌‌=4V
Calculate the value of V2
V2‌‌=‌

Q

C2

‌‌=‌

16

8

‌‌=2V
The potential is calculated as,
∆V=V1−V2
=4−2
=2V