TS EAMCET 03 May 2019 Shift 2 Solved Paper
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Question : 110 of 160
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A proton accelerated by a potential difference 500 kV flies through a uniform transverse magnetic field 0.1T. The field is spread on a region of 1.0 cm thickness. Hie angle through which the proton gets deviated from its original direction is
(Proton mass = 1.6 x10 − 27 kg and charge of proton = 1.6 × 10 − 19 C)
(Proton mass = 1.6 x
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