TS EAMCET 04 May 2019 Shift 1 Solved Paper

Consider the equation,
x2+y2−6x+12y+15=0
The centre is (3,-6) so,
r‌‌=√9+36−15
‌‌=√30
The area is given by,
A=π(√30)2
=30π
The required equation has the radius twice of the area so,
A′‌‌=60π
πR2‌‌=60π
R2‌‌=60
Thus, the equation of concentric circle is,
(x−3)2+(y+6)2=60
x2+y2−6x+12y−15=0