TS EAMCET 04 May 2019 Shift 1 Solved Paper

It is given that the vertices of triangle ABC are
A(α,5,β),B(−2,1,6)‌ and ‌C(1,0,−3)
The mid-point of AC is,
D=(‌

α+1

2

,‌

5

2

,‌

β−3

2

)
Then diagram is,
So
BD‌‌=(‌

α+1

2

+2)i+(‌

5

2

−1)j+(‌

β−3

2

−6)k
‌‌=(‌

α+5

2

)i+(‌

3

2

)j+(‌

β−15

2

)k
since BD is equally inclined to the coordinate axis then,
(‌

α+5

2

)2=(‌

3

2

)2=(‌

β−15

2

)2
‌

α+5

2

=‌

3

2

=‌

β−15

2

This gives,
α=−2,β=18
So
α+β‌‌=−2+18
‌‌=16