∫ \frac{x^3+2x}{x^4+4} dx =

Correct Answer is : 12[tan−1(x22)+log(√x4+42)]+c

1/2[\tan^{-1}(x^2/2)+\log (\sqrt{x^4+4}/2)]+c

1/2tan^{-1}(\frac{x^2+2}{2x}) + c

1/2[\tan^{-1}(x^2/2)-\log (\sqrt{x^4+4}/2)]+c

1/\sqrt2 \tan^{-1}(\frac{x^2+2}{\sqrt2x}) + c

TS EAMCET 04 May 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫

x3+2x

x4+4

dx =

Go to Question:

Prev Question

Next Question