\int e^x (\frac{\sec^2x + tanx - cotx}{sinx}) dx =

Correct Answer is : ex (cosec x + sec x) + c

e^x (\frac{\sec^2x+tanx}{sinx})+c

e^x (\frac{1+\tan^2 x}{sinx})+c

TS EAMCET 06 May 2019 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫ex(

sec2x+tanx−cotx

sinx

) dx =

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