TS EAMCET 10 May 2024 Shift 1 Solved Paper

Section: Mathematics

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Question : 68 of 160

Marks: +1, -0

The equation of the normal drawn to the curve y3=4x5 at the point (4,16) is

[TG EAPCET 10 May 2024 Shift 1]

‌20x+3y=128
‌20x−3y=32
‌3x−20y+308=0
3x+20y=332

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