\int (\frac{4 \tan ^4 x+3 \tan ^2 x-1}{\tan ^2 x+4}) \dx= [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : 4tanx−172Tan−1(tanx2)+c

4 \tan x-\frac{17}{4} {\Tan}^{-1} (\frac{\tan x}{4}) +c

4 \tan x-\frac{17}{4} {\Tan}^{-1} (\frac{\tan x}{2}) +c

4 \tan x-\frac{17}{2} {\Tan}^{-1} (\frac{\tan x}{2}) +c

2 \tan x-\frac{17}{2} {\Tan}^{-1} (\frac{\tan x}{2}) + {\c}

TS EAMCET 10 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫(‌

4tan4x+3tan2x−1

tan2x+4

)‌dx=

[TG EAPCET 10 May 2024 Shift 1]

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