TS EAMCET 10-Sep-2020 Shift 1 Solved Paper

Capacitance of an oil drop of radius r is
C=4πεr
when n drops combine to form a large drop of radius R, then
n× volume of 1 small drop = volume of 1 large drop
n×‌

4

3

πr3=‌

4

3

πR3⇒R=n1∕3⋅r
So, capacitance of large drop is
C′=4πεR=4πε⋅n‌

1

3

⋅r=n‌

1

3

C