TS EAMCET 10-Sep-2020 Shift 2 Solved Paper

The given situation is shown below For convex lens, u=−8cm,f=4cm
‌

1

v

−‌

1

u

=‌

1

f

⇒‌

1

v

=‌

1

4

+‌

1

−8

⇒‌

1

v

=‌

1

8

⇒v=8cm
For concave lens, image of convex lens acts like a virtual object.
So, u=+2cm,f=−4cm
‌

1

v

=‌

1

−4

+‌

1

2

=‌

1

4

cm⇒v=4cm
So, distance from final image and object
=(8+6+4)cm=18cm