\int \frac{d x}{4+3 \cot x} \dx= [TG EAPCET 11 May 2024 Shift 1]

Correct Answer is : −325log|4sinx+3cosx|+425x+c

-\frac{3}{25} \log |4+3 \cot x|+\frac{4}{25} x+c

-\frac{3}{25} \log |4 \sin x+3 \cos x|+\frac{4}{25} x+c

\frac{4}{25} \log |4 \sin x+3 \cos x|-\frac{3}{25} x+c

\frac{4}{25} \log |4+3 \cot x|-\frac{3}{25} x+c

TS EAMCET 11 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

∫‌

4+3‌cot‌x

‌dx=

[TG EAPCET 11 May 2024 Shift 1]

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