TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Equation of given parabola is y2=2px having focus F(‌

p

2

,0) and equation of directrix is x+‌

p

2

=0, so equation of circle having centre (‌

p

2

,0) and radius r=p, because the circle touches the directrix of the given parabola, is
(x−p∕2)2+y2=p2...(i)
Now, on solving the equation of the given parabola and circle (i), we get
⇒‌‌x=‌

p

2

 [∵xp>0]
and y=±p
Point of intersections of circle and parabola are (‌

p

2

,p),(‌

p

2

,−p)