TS EAMCET 11-Sep-2020 Shift 1 Solved Paper

Mass of body, m=10kg
Force. F=4N
Acceleration produced in the body due to applied force,
a=‌

F

m

=‌

4

10

=0.4ms−2
For 0≤t≤1 s, t1=1s
∴ Distance travelled by the body is given as
∴ Work done,
W1=F×s1=4×0.2=0.8J
For 1≤t≤2s,t2=1s
Velocity of the body after t1=1s is v, then
Distance travelled by the body in this situation is given as,
∴ Work done, W2=Fs2=4×0.6=2.4J
∴‌‌‌

W2

W1

=‌

2.4

0.8

=‌

3

1

=3