TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

The magnetic field at some internal point on the axis of a solenoid is given by
B=‌

µ0nI

2

(cos‌θ1−cos‌θ2)
Magnetic field at the centre of a long solenoid is given by setting θ1=0∘ and θ2=π.
=µ0nI..(i)
Similarly, the magnetic field at the end of a long solenoid is given by setting θ1=‌

π

2

and θ2=τ
=‌

µ0nI

2

...(ii)
From Eq. (i) and Eq. (ii), we get
‌

B1

B2

=‌

µ0nI

µ0nI

×2=2