TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

The energy equation in photoelectric effect is given as
eV0=hv−ϕ0⇒V0=‌

hv

e

−‌

ϕ0

e

...(i)
When the frequency is doubled,
V0′=2V0+‌

φ0

e

 [using Eq. (i)]
⇒V0′>2V0
Thus, the stopping potential will become more than double.