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Question : 52 of 160
Marks:
+1,
-0
Solution:
As radical axis of the two circles bisects the all common tangents of the circles.
Now, the mid-point of
A(1,1) and
B(0,1) is
M(‌,1) and mid-point of
C(‌,‌) and
D(−‌,‌) is
N(‌,‌) ∴ Equation of required radical axis
MN is
⇒‌‌2x+6y=7
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