\intx^2/{(\sqrt{4-x^2})^3}dx=

Correct Answer is : x2√4−x2−Tan−1(x√4−x2)+C

x^2/\sqrt{4-x^2}-Sin^{-1}(x/2)+C

x^2/\sqrt{4-x^2}-Tan^{-1}(x/\sqrt{4-x^2})+C

x^2/\sqrt{4-x^2}+Sin^{-1}(2/\sqrt{4-x^2})+C

TS EAMCET 11-Sep-2020 Shift 2 Solved Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

∫

(√4−x2)3

dx=

Go to Question:

Prev Question

Next Question