TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

Time-period of oscillations, T=2π√‌

m

k

where, m= mass of the oscillating system
and ‌‌k= spring constant.
Case I 700g mass is removed, then
m=500g+400g=900g=0.9g So, T1=2π√‌

0.9

k

3=2π√‌

0.9

k

‌‌...(i)[∵T1=3s( given )]
Case II 500g mass is further removed, then
m=400g=0.4kgSo, ‌‌T2=2π√‌

0.4

k

...(ii)
On dividing Eq. (ii) by Eq. (i), we get
⇒‌‌‌

T2

3

=‌

2

3

⇒T2=2s