TS EAMCET 4-Aug-2021 Shift 1 Question Paper

Given, Let, initial and final volume and pressures are V1,V2 and p1,p2, respectively.
where, V1=2m3
‌p1=2×105N∕m2
‌V2=0.5m3
and adiabatic constant γ for diatomic gases
=‌

Cp

CV

=‌

7

5

=1.4
As we know that,
In adiabatic condition, p1V1γ=p2V2γ
∴‌‌p2‌‌=p1(‌

V1

V2

)γ
‌‌=2×105(‌

2

0.5

)1.4
‌‌=2×105×41.4=2×105×6.96
‌‌=13.92×105N∕m2
Since, work done in adiabatic condition,
W‌‌=‌

p1V1−p2V2

γ−1

‌‌=‌

2×105×2−13.92×105×0.5

1.4−1

‌‌=−7.4×105J