TS EAMCET 4-Aug-2021 Shift 1 Question Paper

Given, relative permeability, µr=501
Current through solenoid, I=2.5A
and number of turns per unit length, n=‌

N

l

=900
As we know that, B=µ0H
⇒‌‌H=‌

B

µ0

where,
B= magnetic flux density / magnetic induction,
µ0= free space permeability
and H= magnetising field intensity.
Since, magnetic field due to solenoid, B=µ0nI
Here, µ is permeability of medium
and µ=µrµ0
where, µr is relative permeability.
∴‌‌H‌‌=‌

B

µ0

=‌

nµI

µ0

‌‌=‌

nµrµ0I

µ0

⇒‌‌H‌‌=nµrI
‌‌=900×501×2.5
‌‌=1.12×106A∕m