TS EAMCET 4-Aug-2021 Shift 1 Question Paper

Given, speed of water coming out, v=10ms−1
Radius of tube, r=1cm=1×10−2m,
Height of window, H=3m,
Acceleration due to gravity, g=10ms−2
and density of water, ρ=1000kg∕m3
As we know that,
‌ Power ‌(P)=‌

‌ Work ‌(W)

‌ Time ‌(t)

and W= total energy =mgh+‌

1

2

mv2
∴‌‌P‌‌=‌

mgh+ 1 2 mv2

t

=‌

m

t

(gh+‌

v2

2

)
‌‌=‌

ρA⋅l

t

(h+‌

v2

2

)
‌‌=ρAv(gh+‌

v2

2

)
‌‌=1000×π(‌

1

100

)2×10(10×3+‌

100

2

)
‌‌=1000×‌

10

10000

×π80
‌‌=80πW