The polars of (-1, 2) with respect to the two circles \S_1\equivx^2+y^2+6y+7 = 0 and \S_2\equivx^2+y^2+6x+1 = 0

Correct Answer is : Intersecting at a non zero point

Intersecting at a non zero point

TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Section: Mathematics

Question : 52 of 160

Marks: +1, -0

The polars of (−1,2) with respect to the two circles S1≡x2+y2+6y+7 = 0 and S2≡x2+y2+6x+1 = 0

Go to Question:

Prev Question

Next Question