TS EAMCET 4 May 2018 Shift 1 Solved Paper

Section: Chemistry

Question : 146 of 160

Marks: +1, -0

If the rate constants of a reaction at 500 K and 700 K are 0.002 s−1 and 0.06 s−1 respectively, the value of K−1 activation energy is
(R = 8.314 J mol−1K−1 , log 3 = 0.477)

49.49 kJ mol−1
98.98 kJ mol−1
34.75 kJ mol−1
12.37 kJ mol−1

Validate

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