\int^{3}_{0} (2 + x^2) dx =

Correct Answer is : limn→∞1n [6n+12+22+...+9n2n2]

\lim_{n\to\infty} 1/n [2n+ {1^2+2^2+...+(3n)^2}/n^2]

\lim_{n\to\infty} 1/n [3n+ {1^2+2^2+...+6n^2}/n^2]

\lim_{n\to\infty} 1/n [6n+ {1^2+2^2+...+9n^2}/n^2]

\lim_{n\to\infty} 1/n [3n+ {1^2+2^2+...+3n^2}/n^2]

TS EAMCET 4 May 2018 Shift 1 Solved Paper

Section: Mathematics

Question : 76 of 160

Marks: +1, -0

∫

(2 + x2) dx =

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