TS EAMCET 4 May 2018 Shift 1 Solved Paper

Consider the diagram as shown below,
According to the law of conservation of momentum along horizontal direction,
1×u1=mv2‌cos‌30°
u1=

√3

2

mv2
According to the law of conservation of momentum along vertical direction,
1vv1=mv2‌sin‌30°
v1=

1

2

mv2
From kinetic energy conservation,

1

2

u12=

1

2

v12+

1

2

mv22
u12−v12=

1

2

mv22

3

4

m2v22−

1

4

m2v22=

1

2

mv22
m=2‌kg