TS EAMCET 4 May 2018 Shift 2 Solved Paper

Consider the following figure.
The expression of impedance of the circuit is as follows,
Z=√R2+(XC−XL)2
The expression of capacitance reactance is as follows,
XC=

1

ωC

=

1

2πfC

Substitute the values.
Xc=

1

2π(50)(10×10−6)

=318.47Ω
The expression of inductive reactance is as follows,
XL=ωL=2πfL
Substitute the values.
XL=2π(50)(6×10−6)
=18.84×10−4Ω
The impedence is,
Z=√102+(318.4−18.84×10−4)2
=318.55Ω
Rms current is calculated as,
irms=

Vrms

Z

=

V0∕√2

Z

=

280

√2×318.55

=0.621A
The average power dissipation is calculated as,
P=irms2.R
=(0.621)2×10
=3.8W