TS EAMCET 4 May 2018 Shift 2 Solved Paper

Section: Physics

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Question : 116 of 160

Marks: +1, -0

An energy of 13.6 eV is equal to

0.518×10−25Kcal
6.04×10−25kWh
2.17×10−10J
2.17×10−15kN.m

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