For the formation of {NH}_{3} from {N}_{2} and {H}_{2} at 500 {K}, theconcentration of {N}_{2}, {H}_{2} and {NH}_{3} at equilibrium are 1.5\times 10^{-2} {M}, 3.0\times10^{-2} {M} and 1.2 \times10^{-2} {M}, respectively. The equilibrium constant for the reverse reaction is

Correct Answer is : 2.81×10−3

TS EAMCET 4 May 2018 Shift 2 Solved Paper

Section: Chemistry

Question : 132 of 160

Marks: +1, -0

For the formation of NH3 from N2 and H2 at 500K, theconcentration of N2,H2 and NH3 at equilibrium are 1.5×10−2M,3.0×10−2M and 1.2×10−2M, respectively. The equilibrium constant for the reverse reaction is

3.56×102
2.81×10−3
3.56×10−2
2.81×103

Validate

Go to Question:

Prev Question

Next Question