If the line joining the points A(b \cos \\alpha, b \sin \\alpha) andB(a \cos \\beta, a \sin \\beta) is extended to the point {N}(x, y) such that {AN}: {NB}=b: a then

Correct Answer is : xcosα+β2+ysinα+β2=0

x \cos \frac{\\alpha-\\beta}{2}+y \sin \frac{\\alpha+\\beta}{2}=0

x \cos \frac{\\alpha-\\beta}{2}+y \sin \frac{\\alpha-\\beta}{2}=0

x \cos \frac{\\alpha+\\beta}{2}+y \sin \frac{\\alpha+\\beta}{2}=0

x \cos \frac{\\alpha+\\beta}{2}+y \sin \frac{\\alpha-\\beta}{2}=0

TS EAMCET 4 May 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 42 of 160

Marks: +1, -0

If the line joining the points A(b‌cos‌α,b‌sin‌α) andB(a‌cos‌β,a‌sin‌β) is extended to the point N(x,y) such that AN:NB=b:a then

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